Question 35882
{{{ log(x) - log(x-1) = log(2) }}}
{{{ log(x/(x-1)) = log(2) }}}


Now raise everything to power 2 to remove the log-base2:


{{{ x/(x-1) = 2 }}}
{{{ x/(x-1) = 2 }}}
x = 2(x-1)
x = 2x - 2
2 = x
-->x=2


{{{ log(sqrt(x^5/y^3)) }}}
{{{ log(x^5/y^3)^(1/2) }}}
{{{ log(x^(5/2)/y^(3/2)) }}}
{{{ log(x^(5/2)) - log(y^(3/2)) }}}
{{{ (5/2)log(x) - (3/2)log(y) }}}


jon.