Question 306997
{{{5log(6^(x+1))= 5}}}
Write it using the log equiv of exponents
{{{5(x+1)log(6)= 5}}}
divide both sides by the log(6)
5(x+1) = {{{5/log(6)}}}
using a calc
5(x+1) = 6.425486
:
5x + 5 = 6.425486
:
5x = 6.425486 - 5
:
5x = 1.425486
x = {{{1.425486/5}}}
x = .2851
:
:
Check on a calc: enter 5*log(6^(.2851+1)) = . 5.000