Question 307008
this is a hyperbola (second order terms, squares, have different signs)


isolating the squares will make it more recognizable


16y^2 - 32y + 16 - 9x^2 + 36x - 36 - 144 = 0


16(y - 1)^2 - 9(x - 2)^2 = 144


{[(y - 1)^2] / 9} - {[(x - 2)^2] / 16} = 1