Question 307032
By base change formula, do you mean
{{{y^x= a}}} is equivalent to {{{x= (log a)/(log y) }}}???


If so, then 
{{{2^x=5}}} is equivalent to {{{x= (log 5)/(log 2) }}}, which by calculator is about 2.32.


Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus