Question 306912
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ 2\sqrt{5L}]


Square both sides


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r^2\ =\ 4\cdot5L]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ L(r)\ =\ \frac{r^2}{20}]


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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ L(55)\ =\ \frac{55^2}{20}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ L(100)\ =\ \frac{100^2}{20}]


You get to do your own arithmetic.


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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r(L)\ =\ 2\sqrt{5L}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r(217.8)\ =\ 2\sqrt{5\cdot217.8}]


You get to do your own arithmetic again.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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