Question 306425
change into y-intercept formula
{{{y=mx+b}}}
{{{2x+3y=5}}}
{{{3y=-2x+5}}}
{{{y=(-2/3)x+(5/3)}}}
so the slope = down 2 right 3
the y-intercept is at point ({{{0}}},{{{(5/3)}}})
plot the y-intercept
from that dot go down 2 which is same as {{{(5/3)-2=(-1/3)}}}
then right 3 from {{{(-1/3)}}} 
which is {{{(-1/3)+3=(8/3)}}}
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i would draw my graph
with 3rd incraments{{{1/3}}}{{{2/3}}}{{{3/3}}}{{{4/3}}}{{{5/3}}}{{{6/3}}}{{{7/3}}}{{{8/3}}}
up and right would be positve
down and left are negative