Question 306338
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A_\triangle\ =\ \frac{bh}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A_\triangle\ =\ \frac{\sqrt{30}\cdot\sqrt{6}}{2}\ =\ \frac{\sqrt{5}\cdot\sqrt{6}\cdot\sqrt{6}}{2}\ = \frac{6\sqrt{5}}{2}\ =\ 3\sqrt{5}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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