Question 306304
Given: {{{50g^2 + 40g + 8}}}
I would start by reducing the equation.  Everything is divisible by 2
{{{2*(25g^2 + 20g + 4)}}}
Find the factors of 4: 1, 2, 2, 4
Find the factors of 25: 1, 5, 5, 25
Now since the 4 is positive that means that both factors contain both + signs or both - signs.
But since the 20g is positive, both factors can not contain negative signs.
Then you have to see which of your factors fit.
{{{highlight(2*(5g + 2)*(5g + 2))}}}

Then you can solve for g by setting the factor to 0 or using the quadratic equation.
{{{5g + 2 = 0}}}
{{{5g = -2}}}
{{{highlight_green(g = -2/5)}}}
*[invoke quadratic "x", 50, 40, 8]