Question 306283
understand who you got to the 2/cuberoot 9, but I don't understand how to got to the next step of 2*(cuberoot 81)/9?
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= 2/cuberoot 9
= 2*cr(81)/(cr(9)*cr(81))
= 2*cr(81)/cr(729)
= 2cr(81)/9
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I could have done it like this:
= 2/cuberoot 9
= 2*cr(3)/(cr(9)*cr(3))
= 2*cr(3)/cr(27)
= 2*cr(3)/3