<PRE><B>Question 306152</B>
[x/x+1] + [6/x+7]
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gcd: (x+1)(x+7)
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Rewrite both fraction with the gcd as its denominator:
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[x(x+7)/gcd] + [6(x+1)/gcd]
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Combine the numerators over the gcd:
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[x^2+7x+6x+6]/gcd
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[x^2+13x+6]/[(x^2+8x+7)
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(x-3)/5 = (x-3)/x 
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Cross multiply to get:
x(x-3) = 5(x-3)
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x^2-3x = 5x-15
x^2-8x+15 = 0
Factor:
(x-5)(x-3) = 0
x = 5 or x = 3
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Cheers,
Stan H.</PRE>