Question 305950
5 red apples, 3 green apples, 8 total.
P(first red)=(5/8)
P(second red)=(4/7)
P(2 reds)=(5/8)(4/7)=5/14.
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Let's find the probability you choose 2 green apples.
Then we'll use that to calculate the probability of not getting two greens.
P(first green)=3/8
P(second green)=2/7
P(2 greens)=(3/8)(2/7)=3/28
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P(not 2 greens)+P(2 greens)=1
P(not 2 greens)=1-P(2 greens)
P(not 2 greens)=28/28-3/28
P(not 2 greens)=25/28