Question 305873
Let's assume that b was very close to 2. 
Make it equal to 2 and solve for x.
{{{2x – 3b = 0}}}
{{{2x-3(2)=0}}}
{{{2x=6}}}
{{{x=3}}}
However b will never equal 2, so x will be very close to 3.
When b=0, x=0. 
The solution set includes 0 and a number very close to 3. 
So then x will always be less than 3.
2) x<3