Question 305790
You could also make it (1+3i)/(1+4i).
{{{(1+3i)/(1+4i)=((1+3i)/(1+4i))*((1-4i)/(1-4i))}}}
 {{{(1+3i)/(1+4i)=(1-4i+3i-12i^2)/(1-4i+4i-16i^2)}}}
 {{{(1+3i)/(1+4i)=(1-i+12)/(1+16)}}}
{{{(1+3i)/(1+4i)=(13-i)/17}}}
{{{(1+3i)/(1+4i)=(13/17)-(1/17)i}}}