Question 305783
what is the simplified form of sin^2 (pie/2-x) tan^2x+cos^2(-x)+tan^2x?
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sin(pi/2 -x) = cos(x) (pi, the Greek letter, not pie, the dessert)
cos(-x) = cos(x)
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cos^2*tan^2 + cos^2*tan^2  All of x
= sin^2 + sin^2
= 2sin^2(x)