Question 305728
Dividing by a fraction is the same as multiplying by its reciprocal.
{{{((2w^2+5w)/(w^2-81))/(w^2/(w+9))=((2w^2+5w)/(w^2-81))*((w+9)/w^2)}}}
{{{((2w^2+5w)/(w^2-81))/(w^2/(w+9))=((w(2w+5))/((w-9)(w+9)))*((w+9)/w^2)}}}
{{{((2w^2+5w)/(w^2-81))/(w^2/(w+9))=((cross(w)(2w+5))/((w-9)cross(w+9)))*(cross(w+9)/w^(cross(2)))}}}
{{{((2w^2+5w)/(w^2-81))/(w^2/(w+9))=(2w+5)/(w(w-9))}}}