Question 305770
You should know the basic formulas of odd and even number:
odd + odd = even, 
odd - odd = even,
odd + even = odd,
odd - even = odd,
even + even = even,
even - even = even,
odd*odd = odd,
odd *even = even and
even * even = even.
I. With(a+1)*b, since a is odd, a + 1 is even, and since b is odd, we have (a+1)*b = even.
II. With (a+1) + b, since a is odd, a + 1 is even, and since b is odd, we have (a+1) + b is odd.
III. With (a+1) - b, since a is odd, a + 1 is even, and since b is odd, we have (a+1) - b is odd.
Therefore, II and III are odd, thus the answer is e>II & III