Question 305681
If the measure of one angle of a triangle is three times another and the third angle is twenty degrees larger than the measure of the smaller of the two angles, what is the measure of all the angles of the triangle?

let one angle be x

The other angle = 3x

The third angle = x+20

x+3x+x+20=180

5x+20=180

5x= 160
x=32 first angle
3x= second angle = 96
x+20 third angle = 32+20 = 52