Question 305491
{{S=D/T}}}
{{{S+10=D/(T-2)}}}
{{{S-10=D/(T+3)}}}
____
{{{ST+10T-2S-20=D}}}
{{{ST-10T+3S-30=D}}} subtract equations
{{{0+20T-5S+10=0}}}solve for S
{{{-5S=-20T-10}}}
{{{S=4T+2}}}
{{{D=ST}}}
{{{D=T(4T+2))}}}
{{{D=(4T^2+2T))}}}
{{{S=D/T}}}
{{{S=(2T(T-1))/T}}}
{{{S=2(T-1)}}}
_____
{{{S+10=D/(T-2)}}}
{{{2T-2+10=(4T^2-2T)/(T-2)}}}
{{{2T+8=(4T^2-2T)/(T-2)}}}
{{{2(T+4)(T-2)=2(2T^2-T)}}}
{{{2T^2+4T-16)=4T^2-2T)}}}
{{{0=2T^2-6T+16}}}
{{{0=2(T^2-3T+8)}}}
i cant seem to find the answer unless you go into imaginary numbers
*[invoke quadratic "T", 1, -3, 8]
or i messed up somewhere, this sure is a hard problem. good luck