Question 305506
by definition the median of a triangle vertex is the line from the vertex to the midpoint of the subject line. Clearly the midpoint of bc is located at (-5,(13-3)/2) = (-5,5). So we only need the distance from (4,6) to (-5,5)

{{{dist = sqrt( (y2-y1)^2+(x2-x1)^2) }}}
{{{dist = sqrt( (5-6)^2+(-5-4)^2) }}}
{{{dist = sqrt( (-1)^2+(-9)^2) }}}
{{{dist = sqrt( 1+81) }}}
{{{dist = sqrt( 82)}}}