<PRE><B>Question 305491</B>
A car travels with uniform speed. If it would have traveled 10 km/h faster, it would reach the destination 2 hours earlier and if it would have traveled 10km/h slower, it would reach the destination 3 hours later. What is the distance covered by car.
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Uniform speed DATA:
rate = r mph ; time = h hours ; distance = rh miles
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Slower speed DATA:
rate = r-10 mph ; time = h+3 hrs ; distance = (r-10)(h+3) miles
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Faster speed DATA:
rate = r+10 mph ; time = h-2 hrs ; distance = (r+10)(h-2) miles
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Equations:
(r-10)(h+3) = rh
(r+10)(h-2) = rh
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rh +3r - 10h - 30 = rh
rh -2r + 10h - 20 = rh
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3r - 10h = 30
-2r+ 10h = 20
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Add to get: r = 50 mph
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Slower speed = r-10 = 40 mph
Faster speed = r+10 = 60 mph
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Cheers,
Stan H.</PRE>