Question 305370
First multiplier is x. 
{{{x(x+1)=x^2+x}}}
{{{(x^2-2x-4)-(x^2+x)=-3x-4}}}
Second multiplier is -3.
{{{-3(x+1)=-3x-3}}}
{{{-3x-4-(-3x-3)=-1}}}
So then,
{{{(x^2-2x-4)/(x+1)=(x-3)-1/(x+1)}}}