Question 305289
Write the equation and then solve. 
a) One leg of a right triangle is four less than twice the other.
The hypotenuse is 10. Find the length of each leg. 
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1st side = x
2nd side = 2x-4
{{{x^2 + (2x-4)^2 = 10^2}}}
{{{5x^2 - 16x + 16 = 100}}}
{{{5x^2 - 16x - 84 = 0}}}
*[invoke solve_quadratic_equation 5,-16,-84]
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Ignore the negative solution
x = 6
2x - 4 = 8
--> 6, 8 & 10 triangle