Question 304840
One problem per post


{{{20x^2+ 4y^2 = 5}}}



{{{(20x^2+ 4y^2)/5 = 1}}}



{{{x^2/4+ (4y^2)/5 = 1}}}



{{{x^2/4+ (y^2)/(5/4) = 1}}}



{{{((x-0)^2)/(2^2)+ ((y-0)^2)/((sqrt(5/4))^2) = 1}}}


Equation is now in form {{{(x-h)^2/a^2+(y-k)^2/b^2=1}}}