Question 35703
{{{ x^3 - 125 = 0}}}

Factor as the difference of two cubes:
{{{(x-5)*(x^2 + 5x + 25) = 0}}}
{{{x= 5}}} or {{{x^2 + 5x + 25 = 0}}}
*[invoke solve_quadratic_equation 1, 5, 25]


The final answer is {{{x = 5}}}, {{{x= (-5+- 5i*sqrt(3))/2 }}}


R^2 at SCC