Question 304715
the most pleasing shape for a rectangle was one for which the ratio of the length 
to the width was approximately 8 to 5, the golden ratio.
 If the length of a rectangular painting is 2 ft. longer than its width,
 then for what dimensions would the length and width have the golden ratio?
:
let x = the width
then
(x+2) = the length
:
{{{(x+2)/x}}} = {{{8/5}}}
cross multiply
8x = 5(x+2)
8x = 5x + 10
8x - 5x = 10
3x = 10
x = {{{10/3}}}
x = 3{{{1/3}}} ft is the width, then 5{{{1/3}}} ft is the length, the golden ratio