Question 304635
{{{x^2+4x+1=0}}}
Take 1/2 of the x coefficient, square it, add it to both sides of the equation.
{{{(x^2+4x+4)+1=4}}}
{{{(x+2)^2+1=4}}}
{{{(x+2)^2=3}}}
{{{x+2=0 +- sqrt(3)}}}
{{{x= -2 +- sqrt(3)}}} or approximately
{{{x=-0.27}}} and
{{{x=-3.73}}}