Question 304484
One leg of a right triangle is twice as long as the other leg.
x = 1 leg
2x = 2nd leg
:
The length of the hypotenuse is square root of 20.
{{{x^2 + (2x)^2 = (sqrt(20))^2}}} 
{{{x^2 + 4x^2 = 20}}}
{{{5x^2 = 20}}}
{{{x^2 = 20/5}}}
{{{x^2 = 4}}}
x = 2 is the 1st leg
and
2(2) = 4 is the 2nd leg
;
:
Check: h = {{{sqrt(2^2+4^2)}}}
h = {{{sqrt(20)}}}