Question 304503
Three numbers: x, y, z, (z is the largest)
:
the sum of three numbers is 138. 
x + y + z = 138
:
the second is 5 more than the smallest 
y = x + 5
:
and the third is 10 more than the smallest.
z = x + 10
:
find the numbers.
x + y + z = 138
Substitute
x + (x+5) + (x+10) = 138
:
3x + 15 = 138
3x = 138 - 15
3x = 123
x = {{{123/3}}}
x = 41
then
y = 46
and
z = 51
;
:
Check: 41 + 46 + 51 = 138