Question 304440
What does 12C3=220 mean? 
If I have 12 numbers as follows: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 and I pick three numbers randomly for example 2, 6, and 9, how many possible combinations are there for these three numbers? How do I figure this? 
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12C3 = 12!/[(12-3)!*3!] = (12*11*10)/(1*2*3) = 2*110 = 220
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Cheers,
Stan H.