Question 551
OK, we want 3 numbers, so we'll call them x, y and z.

Now, we know that:

{{{x+y+z=-81}}}

If they are consecutive odd integers, then we also know that:

{{{x+2=y}}}
and
{{{y+2=z}}}

The second-last equation can be substituted into the last one, giving:

{{{(x+2)+2=z}}}

Expand the brackets:

{{{x+4=z}}}

Substituting these values for y and z into the original equation gives:

{{{x+(x+2)+(x+4)=-81}}}

Expand the brackets:

{{{3x+6=-81}}}

Subtract 6 from both sides:

{{{3x = -87}}}

Divide by 3:

{{{x=-29}}}

Using the values of y and z from above we get:

{{{y = -29+2}}}
{{{y=-27}}}

and:

{{{z=-29+4}}}
{{{z=-25}}}

So the 3 integers are -25,-27 and -29.