Question 304400
I am trying to write an equation based on table data. 
X: -2, -1, 0, 1, 2
Y: -8, -2, 0, -2, -8
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Form: y = ax^2 + bx + c
Substitute three of the x/y pairs; then solve for a, b, c:
-8 = 4a -2b + c
-2 =  a -b  + c
0  = 0a +0b + c
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Using the matrix function of a TI calculator I get:
a = -2 ; b = 0 ; c = 0
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Equation:
y = -2x^2
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Cheers,
Stan H.