Question 304253
{{{(x)^2+(x+1)^2=365}}}
{{{x^2+x^2+2x+1=365}}}
{{{2x^2+2x-364=0}}}
2*2*2*7*13=728
7*4=28 13*2=26 so -13 and +28 are the factoring numbers
{{{(2x+28)(x-13)=0}}}
{{{x=-14}}},{{{13}}}
(-14,-13)or(13,14)
checking
{{{(-14)^2+(-14+1)^2=365}}}
{{{196+169=365}}}
{{{365=365}}}correct
{{{(13)^2+(13+1)^2=365}}}
{{{196+169=365}}}
{{{365=365}}}correct