Question 304202
{{{54pi / 6 = 9pi }}}

Cross sectional area = {{{9pi}}

area of a circle = pi*r^2 

{{{ pi*r^2 = 9pi }}}

{{{r^2 = 9 }}}

{{{ r = sqrt(9) }}} 

r = 3 

Circumference = {{{pi*d}}} 

d = r * 2 

d = 3*2 

d = 6 

Circumference = {{{6pi}}}

Answer:C