<PRE><B>Question 35623</B>
{{{ m = (Rise)/(Run) }}}


Also, a slope of 1.5 is actually one and a half or as a fraction it can be written  {{{m =3/2}}}.


The slope between (1,3) and (-3,y) is the RISE over the RUN, which is 
 {{{m = (y-3)/(-3-1)}}} 


Therefore,
{{{ (y-3)/(-4) = 3/2}}}


Since {{{a/b=c/d}}} means the same as {{{ad=bc}}},

{{{ (y-3)/(-4) = 3/2}}} means that {{{2(y-3) = -4*3}}}
{{{2y-6 = -12}}}


Add +6 to each side:
{{{2y -6 + 6 = -12 + 6}}}
{{{2y = -6}}}
{{{y= -3}}}


Check:  Find the slope between (1,3) and (-3,-3).

{{{m = (-3-3)/(-3-1)}}}
{{{m = (-6)/(-4)= 3/2= 1.5}}}

It checks.


R^2 at SCC</PRE>