Question 35609
Remember that {{{log(b,M^N) = N* log(b,M)}}}


Therefore, {{{log(3,49) = log(3,7^2) = 2*log(3,7)}}}


This means that if you know {{{log(3,7)}}} to find {{{log(3,49)}}}, just multiply the value times 2.  


See my Lesson Plans in algebra.com concerning logarithms, especially the ones that are indicated by "...in Living Color"!!


R^2 at SCC