Question 303652
the width of a rectangle is 5 inches shorter than the length and that the
W = L - 5
:
 perimeter or the rectangle is 50 inches.
2L + 2W = 50
:
set up an equation for the perimeter involving the length.
Replace W with (L-5)
2L + 2(L-5) = 50
solve this equation algebraically to find the length and width.
2L + 2L - 10 = 50
4L = 50 + 10
4L = 60
L = {{{60/4}}}
L = 15 in is the lenght
then
W = L - 5
W = 15 - 5
W = 10 in is the width
:
:
Check solution by finding the perimeter with these values for L & W
2(15) + 2(10) = 50