<PRE><B>Question 4611</B>
 Yes, proof as below.

 2^n3^2n -1  = (2*3^2)^n - 1 = (18^n) - 1

 Use a^n-b^n = (a-b)(a^(n-1) + a^(n-2)b+...+ ab^(n-2)+ b^(n-1))
 Now a= 18, b = 1,
 we have (18^n) - 1 = (18-1)(18^17+18^16+...+18+1) 
  = 17*(18^17+18^16+...+18+1)

 This shows 17 is a divisor of  2^n3^2n -1
 Or proved by Mathematical Induction.

 Kenny</PRE>