<PRE><B>Question 303543</B>
LET HIS SPEED ON HIS WAY HOME BE X MPH

Time taken in the return journey = 225/x

His speed while going was x+24

time taken in forward journey  225/ x+24

225/x + 225 / x+24 = 10 hours

225(x+24)+225x= 10*x(x+24)

225x+5400 +225x= 10x^2 +240x

10x^2-210x-5400=0

x^2-21x-540=0

x^2-36x+15x-540=0

x(x-36)+15(x-36)=0

(x-36)(x+15)=0

x= 36 mph on way home

while going it was 36+24 = 60 mph

Ananth








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