Question 303501
jogger runs at 10 mph

so in half hour he goes 5 miles

Let the distance from this 5 mile point to the point they meet be x

time taken by jogger = x/10

car travels at 55 mph

it has to travel x+5 miles to catch up the jogger

time car takes = x+5 / 55

both these times are same

x+5/55 = x/10

10(x+5) = 55x

10x+50 = 55x

45x=50

x= 50/45 =10/9

time = distance / speed

distance car goes = 10/9 +5 miles

time  = 55/9  / 55

1/9 

= 1 /9

-= 1/9 *60 minutes

the truck cathches up in 6.66 minutes

ananth