Question 303480
a chemist needs a 30% iron alloy. how many grams of a 70% iron alloy must be mixed with 16 grams of a 20% iron alloy to obtain the required 30% alloy
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Equations:
alloy + alloy = alloy
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0.70x + 0.20*16 = 0.30(x+16)
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Multiply thru by 100 and solve for "x":
70x + 20*16 = 30x + 30*16
40x = 10*16
x = 4 grams (amt. of 70% alloy needed for the mixture)
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Cheers,
Stan H.
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