Question 303178
use synthetic division to divide x^4+4x^3+6x^2+4x+1 by x+1

x+1 --> x^4 + 4x^3 + 6x^2 + 4x + 1 (x^3)
        x^4 +  x^3
       ------------
              3x^3 + 6x^2 (3x^2)
              3x^3 + 3x^2
              ------------
                     3x^2 + 4x (3x)
                     3x^2 + 3x
                     ----------
                             x + 1 (1)
                             x + 1
                            --------
                                 0
x^3 + 3x^2 + 3x + 1