Question 303102
The 95% confidence interval would be
({{{X +- 1.96(sigma/sqrt(N))}}})
where {{{N=10}}} and {{{sigma=2.8}}}
.
.
.
({{{4.5 +- 1.96(2.8/sqrt(10))}}})
({{{4.5 +- 1.74)}}})
({{{2.76}}},{{{6.24}}}) million