Question 303014
The quadratic formula reads :  {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

So it would be {{{x=(-10+- sqrt(10^2-4*1*10))/(2*a)}}}

so basically -10 +- sqrt of 100-40 which is 60/ over 2 because your leading coefficient of x^2 is actually a 1. Factor out your square root of 60 which would be 2 square root 15. So now we have -10+- {{{( 2sqrt(15))/(2)}}}  Divide everything on the top by your denominator of 2 to get {{{(-5 +- sqrt (15))}}}

The denominator of course cancels. So that's what you're left with