Question 302903
How do I solve 64=(1/16)^x
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One way:
64 = 2^6
1/16 = 2^(-4)
{{{2^6 = x*2^(-4)}}}
6 = -4x
x = -3/2
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Another way:
log(64) = x*log(1/16)
x = log(64)/log(1/16)
x = -3/2