<PRE><B>Question 302873</B>
find the maximum or minimum value of each equation. 
f(x) = (3/4)x^2-5x-2
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The vertex occurs where x = -b/(2a) = 5/(2(3/4)) = 5/(3/2) = 10/3
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f(10/3) = (3/4)(10/3)^2 - 5(10/3) -2
= (3/4)(100/9) - (50/3) - 2
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= (25/3) - (50/3) - (6/3)
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= -31/3
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= -10 1/3
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Solution: ((10/3) , -10 1/3)
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Cheers,
Stan H.
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