Question 302869

{{{(7/(x+3))-((x-9)/(x+3)(x+2))}}}

common denominator = (x+3)(x+2)

={{{(7(x+2)-(x-9))/((x+3)(x+2))}}}

={{{(7x+14-x +9)/((x+3)(x+2))}}}

={{{(6x+23)/((x+3)(x+2))}}}