Question 302799
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You mean


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sqrt{32}}{4}]


We know that *[tex \LARGE 32\ =\ 2\ \times\ 16]  and that *[tex \LARGE \sqrt{ab}\ =\ \sqrt{a}\ \cdot\ \sqrt{b}], so


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{\sqrt{32}}{4}\ =\ \frac{\sqrt{16}\cdot\sqrt{2}}{4}\ =\ \frac{4\sqrt{2}}{4}\ =\ \sqrt{2}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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