Question 302780
{{{-x+2y+3z=2}}}
{{{2x-3y-z=1}}}
{{{x+y+z=2}}}
{{{x-y-z=0}}}
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if u take these 2 equations and use elimination method u can solve for x
{{{x+y+z=2}}}
{{{x-y-z=0}}}
{{{2x=2}}}
{{{x=1}}}
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{{{-1+2y+3z=2}}}
{{{2(1)-3y-z=1}}}
{{{2y+3z=3}}}
{{{-3y-z=-1}}} = {{{z=1-3y}}}
{{{2y+3(1-3y)=3}}}
{{{2y+3-9y=3}}}
{{{-7y=0}}}
{{{y=0}}}
{{{z=1-3(0)}}}
{{{z=1}}}
x=1 y=0 z=1
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Checking
{{{-1+2(0)+3(1)=2}}}
{{{2(1)-3(0)-1=1}}}
{{{1+0+1=2}}}
{{{1-0-1=0}}}
_ _ _ _ _ _
{{{2=2}}}correct
{{{1=1}}}correct
{{{2=2}}}correct
{{{0=0}}}correct