Question 35565
Set this equation equal to zero and factor by grouping the first two and last two terms of it.


{{{W^3 + 5w^2 - W = 5}}}

{{{W^3 + 5w^2 - W - 5 = 0}}}


Group the first two and the last two:
{{{w^2(w+5) -1(w+5) = 0 }}}

{{{(w+5) ( w^2 -1) = 0}}}

{{{ (w+5) (w-1)(w+1) = 0}}}
{{{w=-5}}}, {{{w=1}}}, {{{w= -1}}}


As you might expect with an equation with an x^3, there will be 3 solutions. 


R^2 at SCC