Question 302531
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(-8,-11\right)]. So this means that {{{x[1]=-8}}} and {{{y[1]=-11}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(-9,-13\right)].  So this means that {{{x[2]=-9}}} and {{{y[2]=-13}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-13--11)/(-9--8)}}} Plug in {{{y[2]=-13}}}, {{{y[1]=-11}}}, {{{x[2]=-9}}}, and {{{x[1]=-8}}}



{{{m=(-2)/(-9--8)}}} Subtract {{{-11}}} from {{{-13}}} to get {{{-2}}}



{{{m=(-2)/(-1)}}} Subtract {{{-8}}} from {{{-9}}} to get {{{-1}}}



{{{m=2}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(-8,-11\right)] and *[Tex \LARGE \left(-9,-13\right)] is {{{m=2}}}